We can start solving the problem by looking at the two different positions of the rider, where position 1 is at the top of the ferris wheel and position 2 is at the bottom of the ferris wheel: 1 2 We know that in each location the force of gravity F mg acts on the rider. Solution: This is a projectile motion problem, a type of motion in which, without air resis- tance, we have ax 0 and ay g. $$0 = \frac$ example distance, cannot be hit by the projectile. Kinematic formulas and projectile motion. Justification: This is a 2D kinematics problem involving circular motion. Tutoring Solution DSST Principles of Physical Science: Study. Projectile Motion Practice Problems 9:59. I found out that the solutions to this problem are the roots of following quadratic equation : This means that to solve any problem in kinematics, we only need 3 given variables. I have implemented a solver that calculates the needed launch angle for given initial projectile velocity, position of launcher and position of target in order to reach the target. However, manipulating the basic equations to get results is pretty straight forward in most cases. To do so, I have just started diving into projectile motion and am thus a beginner in this field. ![]() ![]() ![]() I am working on a project which involves launching a tennis ball at a certain velocity and angle in order to hit a given target.
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